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3x=(2x+12)
We move all terms to the left:
3x-((2x+12))=0
We calculate terms in parentheses: -((2x+12)), so:We get rid of parentheses
(2x+12)
We get rid of parentheses
2x+12
Back to the equation:
-(2x+12)
3x-2x-12=0
We add all the numbers together, and all the variables
x-12=0
We move all terms containing x to the left, all other terms to the right
x=12
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