17(2x-10)(x-403)=0

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Solution for 17(2x-10)(x-403)=0 equation:



17(2x-10)(x-403)=0
We multiply parentheses ..
17(+2x^2-806x-10x+4030)=0
We multiply parentheses
34x^2-13702x-170x+68510=0
We add all the numbers together, and all the variables
34x^2-13872x+68510=0
a = 34; b = -13872; c = +68510;
Δ = b2-4ac
Δ = -138722-4·34·68510
Δ = 183115024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{183115024}=13532$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13872)-13532}{2*34}=\frac{340}{68} =5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13872)+13532}{2*34}=\frac{27404}{68} =403 $

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