-7t(t-3)+4t=3(7+t)

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Solution for -7t(t-3)+4t=3(7+t) equation: 



-7t(t-3)+4t=3(7+t)

We move all terms to the left:

-7t(t-3)+4t-(3(7+t))=0

We add all the numbers together, and all the variables

-7t(t-3)+4t-(3(t+7))=0

We add all the numbers together, and all the variables

4t-7t(t-3)-(3(t+7))=0

We multiply parentheses

-7t^2+4t+21t-(3(t+7))=0



We calculate terms in parentheses: -(3(t+7)), so:

3(t+7)

We multiply parentheses

3t+21

Back to the equation:

-(3t+21)



We add all the numbers together, and all the variables

-7t^2+25t-(3t+21)=0

We get rid of parentheses

-7t^2+25t-3t-21=0

We add all the numbers together, and all the variables

-7t^2+22t-21=0

a = -7; b = 22; c = -21;
Δ = b2-4ac
Δ = 222-4·(-7)·(-21)
Δ = -104
Delta is less than zero, so there is no solution for the equation

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