5(x+2)+10=2x-(1-x)=0

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Solution for 5(x+2)+10=2x-(1-x)=0 equation: 



5(x+2)+10=2x-(1-x)=0

We move all terms to the left:

5(x+2)+10-(2x-(1-x))=0

We add all the numbers together, and all the variables

5(x+2)-(2x-(-1x+1))+10=0

We multiply parentheses

5x-(2x-(-1x+1))+10+10=0



We calculate terms in parentheses: -(2x-(-1x+1)), so:

2x-(-1x+1)

We get rid of parentheses

2x+1x-1

We add all the numbers together, and all the variables

3x-1

Back to the equation:

-(3x-1)



We add all the numbers together, and all the variables

5x-(3x-1)+20=0

We get rid of parentheses

5x-3x+1+20=0

We add all the numbers together, and all the variables

2x+21=0

We move all terms containing x to the left, all other terms to the right

2x=-21

x=-21/2

x=-10+1/2

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