-7(3x-5)=32x-18

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Solution for -7(3x-5)=32x-18 equation: 



-7(3x-5)=32x-18

We move all terms to the left:

-7(3x-5)-(32x-18)=0

We multiply parentheses

-21x-(32x-18)+35=0

We get rid of parentheses

-21x-32x+18+35=0

We add all the numbers together, and all the variables

-53x+53=0

We move all terms containing x to the left, all other terms to the right

-53x=-53

x=-53/-53

x=1

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