-7(t-3)-4(4t+1)=-6

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Solution for -7(t-3)-4(4t+1)=-6 equation: 



-7(t-3)-4(4t+1)=-6

We move all terms to the left:

-7(t-3)-4(4t+1)-(-6)=0

We add all the numbers together, and all the variables

-7(t-3)-4(4t+1)+6=0

We multiply parentheses

-7t-16t+21-4+6=0

We add all the numbers together, and all the variables

-23t+23=0

We move all terms containing t to the left, all other terms to the right

-23t=-23

t=-23/-23

t=1

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