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9x-3/x=3
We move all terms to the left:
9x-3/x-(3)=0
Domain of the equation: x!=0We multiply all the terms by the denominator
x∈R
9x*x-3*x-3=0
We add all the numbers together, and all the variables
-3x+9x*x-3=0
Wy multiply elements
9x^2-3x-3=0
a = 9; b = -3; c = -3;
Δ = b2-4ac
Δ = -32-4·9·(-3)
Δ = 117
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{117}=\sqrt{9*13}=\sqrt{9}*\sqrt{13}=3\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3\sqrt{13}}{2*9}=\frac{3-3\sqrt{13}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3\sqrt{13}}{2*9}=\frac{3+3\sqrt{13}}{18} $
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