-5(4y-3)=3(1-8y)+15

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Solution for -5(4y-3)=3(1-8y)+15 equation: 



-5(4y-3)=3(1-8y)+15

We move all terms to the left:

-5(4y-3)-(3(1-8y)+15)=0

We add all the numbers together, and all the variables

-5(4y-3)-(3(-8y+1)+15)=0

We multiply parentheses

-20y-(3(-8y+1)+15)+15=0



We calculate terms in parentheses: -(3(-8y+1)+15), so:

3(-8y+1)+15

We multiply parentheses

-24y+3+15

We add all the numbers together, and all the variables

-24y+18

Back to the equation:

-(-24y+18)



We get rid of parentheses

-20y+24y-18+15=0

We add all the numbers together, and all the variables

4y-3=0

We move all terms containing y to the left, all other terms to the right

4y=3

y=3/4

y=3/4

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