(x+1)(x+1)=(-6x+10)(-6x+10)

Solution for (x+1)(x+1)=(-6x+10)(-6x+10) equation:

(x+1)(x+1)=(-6x+10)(-6x+10)

We move all terms to the left:

(x+1)(x+1)-((-6x+10)(-6x+10))=0

We multiply parentheses ..

(+x^2+x+x+1)-((-6x+10)(-6x+10))=0


We calculate terms in parentheses: -((-6x+10)(-6x+10)), so:

(-6x+10)(-6x+10)

We multiply parentheses ..

(+36x^2-60x-60x+100)

We get rid of parentheses

36x^2-60x-60x+100

We add all the numbers together, and all the variables

36x^2-120x+100

Back to the equation:

-(36x^2-120x+100)


We get rid of parentheses

x^2-36x^2+x+x+120x+1-100=0

We add all the numbers together, and all the variables

-35x^2+122x-99=0

a = -35; b = 122; c = -99;
Δ = b2-4ac
Δ = 1222-4·(-35)·(-99)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(122)-32}{2*-35}=\frac{-154}{-70}
=2+1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(122)+32}{2*-35}=\frac{-90}{-70}
=1+2/7
$