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-6x=1/2x-25
We move all terms to the left:
-6x-(1/2x-25)=0
Domain of the equation: 2x-25)!=0We get rid of parentheses
x∈R
-6x-1/2x+25=0
We multiply all the terms by the denominator
-6x*2x+25*2x-1=0
Wy multiply elements
-12x^2+50x-1=0
a = -12; b = 50; c = -1;
Δ = b2-4ac
Δ = 502-4·(-12)·(-1)
Δ = 2452
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2452}=\sqrt{4*613}=\sqrt{4}*\sqrt{613}=2\sqrt{613}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-2\sqrt{613}}{2*-12}=\frac{-50-2\sqrt{613}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+2\sqrt{613}}{2*-12}=\frac{-50+2\sqrt{613}}{-24} $
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