1/9(3y-6)=-1/3(4-2y)

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Solution for 1/9(3y-6)=-1/3(4-2y) equation: 



1/9(3y-6)=-1/3(4-2y)

We move all terms to the left:

1/9(3y-6)-(-1/3(4-2y))=0



Domain of the equation: 9(3y-6)!=0

y∈R





Domain of the equation: 3(4-2y))!=0

y∈R



We add all the numbers together, and all the variables

1/9(3y-6)-(-1/3(-2y+4))=0

We calculate fractions


(3y(-)/(9(3y-6)*3(-2y+4)))+(-(-9y3)/(9(3y-6)*3(-2y+4)))=0



We calculate terms in parentheses: +(3y(-)/(9(3y-6)*3(-2y+4))), so:

3y(-)/(9(3y-6)*3(-2y+4))

We add all the numbers together, and all the variables

3y0/(9(3y-6)*3(-2y+4))

We multiply all the terms by the denominator


3y0

We add all the numbers together, and all the variables

3y

Back to the equation:

+(3y)





We calculate terms in parentheses: +(-(-9y3)/(9(3y-6)*3(-2y+4))), so:

-(-9y3)/(9(3y-6)*3(-2y+4))

We add all the numbers together, and all the variables

-(-9y^3)/(9(3y-6)*3(-2y+4))

We multiply all the terms by the denominator


-(-9y^3)

We do not support eypression: y^3

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