-6r2-7r+3=0

Solution for -6r2-7r+3=0 equation:

-6r^2-7r+3=0

a = -6; b = -7; c = +3;
Δ = b2-4ac
Δ = -72-4·(-6)·3
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-11}{2*-6}=\frac{-4}{-12}
=1/3
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+11}{2*-6}=\frac{18}{-12}
=-1+1/2
$