y(y+2)-2(16-y)=7-(15-y(2+y))

Solution for y(y+2)-2(16-y)=7-(15-y(2+y)) equation:

y(y+2)-2(16-y)=7-(15-y(2+y))

We move all terms to the left:

y(y+2)-2(16-y)-(7-(15-y(2+y)))=0

We add all the numbers together, and all the variables

y(y+2)-2(-1y+16)-(7-(15-y(y+2)))=0

We multiply parentheses

y^2+2y+2y-(7-(15-y(y+2)))-32=0


We calculate terms in parentheses: -(7-(15-y(y+2))), so:

7-(15-y(y+2))

determiningTheFunctionDomain
-(15-y(y+2))+7


We calculate terms in parentheses: -(15-y(y+2)), so:

15-y(y+2)

determiningTheFunctionDomain
-y(y+2)+15

We multiply parentheses

-y^2-2y+15

We add all the numbers together, and all the variables

-1y^2-2y+15

Back to the equation:

-(-1y^2-2y+15)


We get rid of parentheses

1y^2+2y-15+7

We add all the numbers together, and all the variables

y^2+2y-8

Back to the equation:

-(y^2+2y-8)


We add all the numbers together, and all the variables

y^2+4y-(y^2+2y-8)-32=0

We get rid of parentheses

y^2-y^2+4y-2y+8-32=0

We add all the numbers together, and all the variables

2y-24=0

We move all terms containing y to the left, all other terms to the right

2y=24

y=24/2

y=12