y(y+2)-2(16-y)=7-(15-y(2+y)

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Solution for y(y+2)-2(16-y)=7-(15-y(2+y) equation: 



y(y+2)-2(16-y)=7-(15-y(2+y)

We move all terms to the left:

y(y+2)-2(16-y)-(7-(15-y(2+y))=0

We add all the numbers together, and all the variables

y(y+2)-2(-1y+16)-(7-(15-y(y+2))=0

We multiply parentheses

y^2+2y+2y-(7-(15-y(y+2))-32=0

We add all the numbers together, and all the variables

y^2+4y-(7-(15-y(y+2))-32=0

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