7(5n+5)=3(7n-4)+15n

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Solution for 7(5n+5)=3(7n-4)+15n equation: 



7(5n+5)=3(7n-4)+15n

We move all terms to the left:

7(5n+5)-(3(7n-4)+15n)=0

We multiply parentheses

35n-(3(7n-4)+15n)+35=0



We calculate terms in parentheses: -(3(7n-4)+15n), so:

3(7n-4)+15n

We add all the numbers together, and all the variables

15n+3(7n-4)

We multiply parentheses

15n+21n-12

We add all the numbers together, and all the variables

36n-12

Back to the equation:

-(36n-12)



We get rid of parentheses

35n-36n+12+35=0

We add all the numbers together, and all the variables

-1n+47=0

We move all terms containing n to the left, all other terms to the right

-n=-47

n=-47/-1

n=+47

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