(x-2)(x-3)+25=(x+1)2-12

Solution for (x-2)(x-3)+25=(x+1)2-12 equation:

(x-2)(x-3)+25=(x+1)2-12

We move all terms to the left:

(x-2)(x-3)+25-((x+1)2-12)=0

We multiply parentheses ..

(+x^2-3x-2x+6)-((x+1)2-12)+25=0


We calculate terms in parentheses: -((x+1)2-12), so:

(x+1)2-12

We multiply parentheses

2x+2-12

We add all the numbers together, and all the variables

2x-10

Back to the equation:

-(2x-10)


We get rid of parentheses

x^2-3x-2x-2x+6+10+25=0

We add all the numbers together, and all the variables

x^2-7x+41=0

a = 1; b = -7; c = +41;
Δ = b2-4ac
Δ = -72-4·1·41
Δ = -115
Delta is less than zero, so there is no solution for the equation