4(12000-z)+10(120000-z)=1176000

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Solution for 4(12000-z)+10(120000-z)=1176000 equation: 



4(12000-z)+10(120000-z)=1176000

We move all terms to the left:

4(12000-z)+10(120000-z)-(1176000)=0

We add all the numbers together, and all the variables

4(-1z+12000)+10(-1z+120000)-1176000=0

We multiply parentheses

-4z-10z+48000+1200000-1176000=0

We add all the numbers together, and all the variables

-14z+72000=0

We move all terms containing z to the left, all other terms to the right

-14z=-72000

z=-72000/-14

z=5142+6/7

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