8f+f(f-6)=57-(17-f2)

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Solution for 8f+f(f-6)=57-(17-f2) equation: 



8f+f(f-6)=57-(17-f2)

We move all terms to the left:

8f+f(f-6)-(57-(17-f2))=0

We add all the numbers together, and all the variables

-(57-(-1f^2+17))+8f+f(f-6)=0

We multiply parentheses

-(57-(-1f^2+17))+f^2+8f-6f=0



We calculate terms in parentheses: -(57-(-1f^2+17)), so:

57-(-1f^2+17)

determiningTheFunctionDomain
-(-1f^2+17)+57

We get rid of parentheses

1f^2-17+57

We add all the numbers together, and all the variables

f^2+40

Back to the equation:

-(f^2+40)



We add all the numbers together, and all the variables

f^2+2f-(f^2+40)=0

We get rid of parentheses

f^2-f^2+2f-40=0

We add all the numbers together, and all the variables

2f-40=0

We move all terms containing f to the left, all other terms to the right

2f=40

f=40/2

f=20

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