-61=4(m+3)+7(2m+5)

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Solution for -61=4(m+3)+7(2m+5) equation: 



-61=4(m+3)+7(2m+5)

We move all terms to the left:

-61-(4(m+3)+7(2m+5))=0



We calculate terms in parentheses: -(4(m+3)+7(2m+5)), so:

4(m+3)+7(2m+5)

We multiply parentheses

4m+14m+12+35

We add all the numbers together, and all the variables

18m+47

Back to the equation:

-(18m+47)



We get rid of parentheses

-18m-47-61=0

We add all the numbers together, and all the variables

-18m-108=0

We move all terms containing m to the left, all other terms to the right

-18m=108

m=108/-18

m=-6

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