2=2(-2k-2)-3(-3k-2)

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Solution for 2=2(-2k-2)-3(-3k-2) equation: 



2=2(-2k-2)-3(-3k-2)

We move all terms to the left:

2-(2(-2k-2)-3(-3k-2))=0



We calculate terms in parentheses: -(2(-2k-2)-3(-3k-2)), so:

2(-2k-2)-3(-3k-2)

We multiply parentheses

-4k+9k-4+6

We add all the numbers together, and all the variables

5k+2

Back to the equation:

-(5k+2)



We get rid of parentheses

-5k-2+2=0

We add all the numbers together, and all the variables

-5k=0

k=0/-5

k=0

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