(4x+1)(4x+1)=-12

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Solution for (4x+1)(4x+1)=-12 equation: 



(4x+1)(4x+1)=-12

We move all terms to the left:

(4x+1)(4x+1)-(-12)=0

We add all the numbers together, and all the variables

(4x+1)(4x+1)+12=0

We multiply parentheses ..

(+16x^2+4x+4x+1)+12=0

We get rid of parentheses

16x^2+4x+4x+1+12=0

We add all the numbers together, and all the variables

16x^2+8x+13=0

a = 16; b = 8; c = +13;
Δ = b2-4ac
Δ = 82-4·16·13
Δ = -768
Delta is less than zero, so there is no solution for the equation

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