-2(x-3)4x=-(-x+1)

Solution for -2(x-3)4x=-(-x+1) equation:

-2(x-3)4x=-(-x+1)

We move all terms to the left:

-2(x-3)4x-(-(-x+1))=0

We add all the numbers together, and all the variables

-2(x-3)4x-(-(-1x+1))=0

We multiply parentheses

-8x^2+24x-(-(-1x+1))=0


We calculate terms in parentheses: -(-(-1x+1)), so:

-(-1x+1)

We get rid of parentheses

1x-1

We add all the numbers together, and all the variables

x-1

Back to the equation:

-(x-1)


We get rid of parentheses

-8x^2+24x-x+1=0

We add all the numbers together, and all the variables

-8x^2+23x+1=0

a = -8; b = 23; c = +1;
Δ = b2-4ac
Δ = 232-4·(-8)·1
Δ = 561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{561}}{2*-8}=\frac{-23-\sqrt{561}}{-16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{561}}{2*-8}=\frac{-23+\sqrt{561}}{-16}
$