-5(v+2)=3v-6+2(5v+2)

Solution for -5(v+2)=3v-6+2(5v+2) equation:

-5(v+2)=3v-6+2(5v+2)

We move all terms to the left:

-5(v+2)-(3v-6+2(5v+2))=0

We multiply parentheses

-5v-(3v-6+2(5v+2))-10=0


We calculate terms in parentheses: -(3v-6+2(5v+2)), so:

3v-6+2(5v+2)

determiningTheFunctionDomain
3v+2(5v+2)-6

We multiply parentheses

3v+10v+4-6

We add all the numbers together, and all the variables

13v-2

Back to the equation:

-(13v-2)


We get rid of parentheses

-5v-13v+2-10=0

We add all the numbers together, and all the variables

-18v-8=0

We move all terms containing v to the left, all other terms to the right

-18v=8

v=8/-18

v=-4/9