x2+3x=(x+3)(x+1)

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Solution for x2+3x=(x+3)(x+1) equation: 



x2+3x=(x+3)(x+1)

We move all terms to the left:

x2+3x-((x+3)(x+1))=0

We add all the numbers together, and all the variables

x^2+3x-((x+3)(x+1))=0

We multiply parentheses ..

x^2-((+x^2+x+3x+3))+3x=0



We calculate terms in parentheses: -((+x^2+x+3x+3)), so:

(+x^2+x+3x+3)

We get rid of parentheses

x^2+x+3x+3

We add all the numbers together, and all the variables

x^2+4x+3

Back to the equation:

-(x^2+4x+3)



We add all the numbers together, and all the variables

x^2+3x-(x^2+4x+3)=0

We get rid of parentheses

x^2-x^2+3x-4x-3=0

We add all the numbers together, and all the variables

-1x-3=0

We move all terms containing x to the left, all other terms to the right

-x=3

x=3/-1

x=-3

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