-2(2v-5)+3v=4+3(3v-3)

Solution for -2(2v-5)+3v=4+3(3v-3) equation:

-2(2v-5)+3v=4+3(3v-3)

We move all terms to the left:

-2(2v-5)+3v-(4+3(3v-3))=0

We add all the numbers together, and all the variables

3v-2(2v-5)-(4+3(3v-3))=0

We multiply parentheses

3v-4v-(4+3(3v-3))+10=0


We calculate terms in parentheses: -(4+3(3v-3)), so:

4+3(3v-3)

determiningTheFunctionDomain
3(3v-3)+4

We multiply parentheses

9v-9+4

We add all the numbers together, and all the variables

9v-5

Back to the equation:

-(9v-5)


We add all the numbers together, and all the variables

-1v-(9v-5)+10=0

We get rid of parentheses

-1v-9v+5+10=0

We add all the numbers together, and all the variables

-10v+15=0

We move all terms containing v to the left, all other terms to the right

-10v=-15

v=-15/-10

v=1+1/2