-4(5u-4)+9u=3(u+2)

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Solution for -4(5u-4)+9u=3(u+2) equation:



-4(5u-4)+9u=3(u+2)
We move all terms to the left:
-4(5u-4)+9u-(3(u+2))=0
We add all the numbers together, and all the variables
9u-4(5u-4)-(3(u+2))=0
We multiply parentheses
9u-20u-(3(u+2))+16=0
We calculate terms in parentheses: -(3(u+2)), so:
3(u+2)
We multiply parentheses
3u+6
Back to the equation:
-(3u+6)
We add all the numbers together, and all the variables
-11u-(3u+6)+16=0
We get rid of parentheses
-11u-3u-6+16=0
We add all the numbers together, and all the variables
-14u+10=0
We move all terms containing u to the left, all other terms to the right
-14u=-10
u=-10/-14
u=5/7

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