-5(3+2r)=-4-6(2+r)-3

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Solution for -5(3+2r)=-4-6(2+r)-3 equation: 



-5(3+2r)=-4-6(2+r)-3

We move all terms to the left:

-5(3+2r)-(-4-6(2+r)-3)=0

We add all the numbers together, and all the variables

-5(2r+3)-(-4-6(r+2)-3)=0

We multiply parentheses

-10r-(-4-6(r+2)-3)-15=0



We calculate terms in parentheses: -(-4-6(r+2)-3), so:

-4-6(r+2)-3

determiningTheFunctionDomain
-6(r+2)-4-3

We add all the numbers together, and all the variables

-6(r+2)-7

We multiply parentheses

-6r-12-7

We add all the numbers together, and all the variables

-6r-19

Back to the equation:

-(-6r-19)



We get rid of parentheses

-10r+6r+19-15=0

We add all the numbers together, and all the variables

-4r+4=0

We move all terms containing r to the left, all other terms to the right

-4r=-4

r=-4/-4

r=1

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