-5(2u-1)+5u=8+2(5u-6)

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Solution for -5(2u-1)+5u=8+2(5u-6) equation: 



-5(2u-1)+5u=8+2(5u-6)

We move all terms to the left:

-5(2u-1)+5u-(8+2(5u-6))=0

We add all the numbers together, and all the variables

5u-5(2u-1)-(8+2(5u-6))=0

We multiply parentheses

5u-10u-(8+2(5u-6))+5=0



We calculate terms in parentheses: -(8+2(5u-6)), so:

8+2(5u-6)

determiningTheFunctionDomain
2(5u-6)+8

We multiply parentheses

10u-12+8

We add all the numbers together, and all the variables

10u-4

Back to the equation:

-(10u-4)



We add all the numbers together, and all the variables

-5u-(10u-4)+5=0

We get rid of parentheses

-5u-10u+4+5=0

We add all the numbers together, and all the variables

-15u+9=0

We move all terms containing u to the left, all other terms to the right

-15u=-9

u=-9/-15

u=3/5

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