4x+8x+12+32+12=10x-68

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Solution for 4x+8x+12+32+12=10x-68 equation: 



4x+8x+12+32+12=10x-68

We move all terms to the left:

4x+8x+12+32+12-(10x-68)=0

We add all the numbers together, and all the variables

12x-(10x-68)+56=0

We get rid of parentheses

12x-10x+68+56=0

We add all the numbers together, and all the variables

2x+124=0

We move all terms containing x to the left, all other terms to the right

2x=-124

x=-124/2

x=-62

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