4m-6=2(13+m)

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Solution for 4m-6=2(13+m) equation: 



4m-6=2(13+m)

We move all terms to the left:

4m-6-(2(13+m))=0

We add all the numbers together, and all the variables

4m-(2(m+13))-6=0



We calculate terms in parentheses: -(2(m+13)), so:

2(m+13)

We multiply parentheses

2m+26

Back to the equation:

-(2m+26)



We get rid of parentheses

4m-2m-26-6=0

We add all the numbers together, and all the variables

2m-32=0

We move all terms containing m to the left, all other terms to the right

2m=32

m=32/2

m=16

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