2(u+3)=-2(6u-8)+6u

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Solution for 2(u+3)=-2(6u-8)+6u equation: 



2(u+3)=-2(6u-8)+6u

We move all terms to the left:

2(u+3)-(-2(6u-8)+6u)=0

We multiply parentheses

2u-(-2(6u-8)+6u)+6=0



We calculate terms in parentheses: -(-2(6u-8)+6u), so:

-2(6u-8)+6u

We add all the numbers together, and all the variables

6u-2(6u-8)

We multiply parentheses

6u-12u+16

We add all the numbers together, and all the variables

-6u+16

Back to the equation:

-(-6u+16)



We get rid of parentheses

2u+6u-16+6=0

We add all the numbers together, and all the variables

8u-10=0

We move all terms containing u to the left, all other terms to the right

8u=10

u=10/8

u=1+1/4

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