-5(1+x)-3x=2(x+1)+2

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Solution for -5(1+x)-3x=2(x+1)+2 equation: 



-5(1+x)-3x=2(x+1)+2

We move all terms to the left:

-5(1+x)-3x-(2(x+1)+2)=0

We add all the numbers together, and all the variables

-5(x+1)-3x-(2(x+1)+2)=0

We add all the numbers together, and all the variables

-3x-5(x+1)-(2(x+1)+2)=0

We multiply parentheses

-3x-5x-(2(x+1)+2)-5=0



We calculate terms in parentheses: -(2(x+1)+2), so:

2(x+1)+2

We multiply parentheses

2x+2+2

We add all the numbers together, and all the variables

2x+4

Back to the equation:

-(2x+4)



We add all the numbers together, and all the variables

-8x-(2x+4)-5=0

We get rid of parentheses

-8x-2x-4-5=0

We add all the numbers together, and all the variables

-10x-9=0

We move all terms containing x to the left, all other terms to the right

-10x=9

x=9/-10

x=-9/10

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