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4(q+3)=2(5q+3)
We move all terms to the left:
4(q+3)-(2(5q+3))=0
We multiply parentheses
4q-(2(5q+3))+12=0
We calculate terms in parentheses: -(2(5q+3)), so:We get rid of parentheses
2(5q+3)
We multiply parentheses
10q+6
Back to the equation:
-(10q+6)
4q-10q-6+12=0
We add all the numbers together, and all the variables
-6q+6=0
We move all terms containing q to the left, all other terms to the right
-6q=-6
q=-6/-6
q=1
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