3x+3(x-2)=10-(2x-5)

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Solution for 3x+3(x-2)=10-(2x-5) equation: 



3x+3(x-2)=10-(2x-5)

We move all terms to the left:

3x+3(x-2)-(10-(2x-5))=0

We multiply parentheses

3x+3x-(10-(2x-5))-6=0



We calculate terms in parentheses: -(10-(2x-5)), so:

10-(2x-5)

determiningTheFunctionDomain
-(2x-5)+10

We get rid of parentheses

-2x+5+10

We add all the numbers together, and all the variables

-2x+15

Back to the equation:

-(-2x+15)



We add all the numbers together, and all the variables

6x-(-2x+15)-6=0

We get rid of parentheses

6x+2x-15-6=0

We add all the numbers together, and all the variables

8x-21=0

We move all terms containing x to the left, all other terms to the right

8x=21

x=21/8

x=2+5/8

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