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5a-2=3(a+2)-5
We move all terms to the left:
5a-2-(3(a+2)-5)=0
We calculate terms in parentheses: -(3(a+2)-5), so:We get rid of parentheses
3(a+2)-5
We multiply parentheses
3a+6-5
We add all the numbers together, and all the variables
3a+1
Back to the equation:
-(3a+1)
5a-3a-1-2=0
We add all the numbers together, and all the variables
2a-3=0
We move all terms containing a to the left, all other terms to the right
2a=3
a=3/2
a=1+1/2
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