-4x-28=4(x-3)+8x

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Solution for -4x-28=4(x-3)+8x equation: 



-4x-28=4(x-3)+8x

We move all terms to the left:

-4x-28-(4(x-3)+8x)=0



We calculate terms in parentheses: -(4(x-3)+8x), so:

4(x-3)+8x

We add all the numbers together, and all the variables

8x+4(x-3)

We multiply parentheses

8x+4x-12

We add all the numbers together, and all the variables

12x-12

Back to the equation:

-(12x-12)



We get rid of parentheses

-4x-12x+12-28=0

We add all the numbers together, and all the variables

-16x-16=0

We move all terms containing x to the left, all other terms to the right

-16x=16

x=16/-16

x=-1

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