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2/5(2-5x)=x
We move all terms to the left:
2/5(2-5x)-(x)=0
Domain of the equation: 5(2-5x)!=0We add all the numbers together, and all the variables
x∈R
2/5(-5x+2)-x=0
We add all the numbers together, and all the variables
-1x+2/5(-5x+2)=0
We multiply all the terms by the denominator
-1x*5(-5x+2)+2=0
Wy multiply elements
-5x^2(-+2=0
We use the square of the difference formula
-5x^2(-2=0
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