-12=3(9-2j)-3

Solution for -12=3(9-2j)-3 equation:

-12=3(9-2j)-3

We move all terms to the left:

-12-(3(9-2j)-3)=0

We add all the numbers together, and all the variables

-(3(-2j+9)-3)-12=0


We calculate terms in parentheses: -(3(-2j+9)-3), so:

3(-2j+9)-3

We multiply parentheses

-6j+27-3

We add all the numbers together, and all the variables

-6j+24

Back to the equation:

-(-6j+24)


We get rid of parentheses

6j-24-12=0

We add all the numbers together, and all the variables

6j-36=0

We move all terms containing j to the left, all other terms to the right

6j=36

j=36/6

j=6