-4(a-5)=32+2a

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Solution for -4(a-5)=32+2a equation: 



-4(a-5)=32+2a

We move all terms to the left:

-4(a-5)-(32+2a)=0

We add all the numbers together, and all the variables

-4(a-5)-(2a+32)=0

We multiply parentheses

-4a-(2a+32)+20=0

We get rid of parentheses

-4a-2a-32+20=0

We add all the numbers together, and all the variables

-6a-12=0

We move all terms containing a to the left, all other terms to the right

-6a=12

a=12/-6

a=-2

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