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3x(x-2)+5=2(5x-4)
We move all terms to the left:
3x(x-2)+5-(2(5x-4))=0
We multiply parentheses
3x^2-6x-(2(5x-4))+5=0
We calculate terms in parentheses: -(2(5x-4)), so:We get rid of parentheses
2(5x-4)
We multiply parentheses
10x-8
Back to the equation:
-(10x-8)
3x^2-6x-10x+8+5=0
We add all the numbers together, and all the variables
3x^2-16x+13=0
a = 3; b = -16; c = +13;
Δ = b2-4ac
Δ = -162-4·3·13
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-10}{2*3}=\frac{6}{6} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+10}{2*3}=\frac{26}{6} =4+1/3 $
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