4x-5(3-2x)=9x-2+12

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Solution for 4x-5(3-2x)=9x-2+12 equation: 



4x-5(3-2x)=9x-2+12

We move all terms to the left:

4x-5(3-2x)-(9x-2+12)=0

We add all the numbers together, and all the variables

4x-5(-2x+3)-(9x+10)=0

We multiply parentheses

4x+10x-(9x+10)-15=0

We get rid of parentheses

4x+10x-9x-10-15=0

We add all the numbers together, and all the variables

5x-25=0

We move all terms containing x to the left, all other terms to the right

5x=25

x=25/5

x=5

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