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8(x-1)+6=2(3x+4)
We move all terms to the left:
8(x-1)+6-(2(3x+4))=0
We multiply parentheses
8x-(2(3x+4))-8+6=0
We calculate terms in parentheses: -(2(3x+4)), so:We add all the numbers together, and all the variables
2(3x+4)
We multiply parentheses
6x+8
Back to the equation:
-(6x+8)
8x-(6x+8)-2=0
We get rid of parentheses
8x-6x-8-2=0
We add all the numbers together, and all the variables
2x-10=0
We move all terms containing x to the left, all other terms to the right
2x=10
x=10/2
x=5
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