-3(y+2)=-8y-11

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Solution for -3(y+2)=-8y-11 equation:



-3(y+2)=-8y-11
We move all terms to the left:
-3(y+2)-(-8y-11)=0
We multiply parentheses
-3y-(-8y-11)-6=0
We get rid of parentheses
-3y+8y+11-6=0
We add all the numbers together, and all the variables
5y+5=0
We move all terms containing y to the left, all other terms to the right
5y=-5
y=-5/5
y=-1

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