3(x-1)/2=6(x+3)/12

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Solution for 3(x-1)/2=6(x+3)/12 equation: 



3(x-1)/2=6(x+3)/12

We move all terms to the left:

3(x-1)/2-(6(x+3)/12)=0

We calculate fractions


3x/()+(-(6(x+3)*2)/()=0



We calculate terms in parentheses: +(-(6(x+3)*2)/(), so:

-(6(x+3)*2)/(

We multiply all the terms by the denominator


-(6(x+3)*2)



We calculate terms in parentheses: -(6(x+3)*2), so:

6(x+3)*2

We multiply parentheses

12x+36

Back to the equation:

-(12x+36)



We get rid of parentheses

-12x-36

Back to the equation:

+(-12x-36)



We get rid of parentheses

3x/()-12x-36=0

We multiply all the terms by the denominator


3x-12x*()-36*()=0

We add all the numbers together, and all the variables

3x-12x*()=0

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