(3/8)h-8=11

Solution for (3/8)h-8=11 equation:

(3/8)h-8=11

We move all terms to the left:

(3/8)h-8-(11)=0


Domain of the equation: 8)h!=0

h!=0/1

h!=0

h∈R


We add all the numbers together, and all the variables

(+3/8)h-8-11=0

We add all the numbers together, and all the variables

(+3/8)h-19=0

We multiply parentheses

3h^2-19=0

a = 3; b = 0; c = -19;
Δ = b2-4ac
Δ = 02-4·3·(-19)
Δ = 228
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{228}=\sqrt{4*57}=\sqrt{4}*\sqrt{57}=2\sqrt{57}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{57}}{2*3}=\frac{0-2\sqrt{57}}{6}
=-\frac{2\sqrt{57}}{6}
=-\frac{\sqrt{57}}{3}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{57}}{2*3}=\frac{0+2\sqrt{57}}{6}
=\frac{2\sqrt{57}}{6}
=\frac{\sqrt{57}}{3}
$