If it's not what You are looking for type in the equation solver your own equation and let us solve it.
11x(x+10)=132
We move all terms to the left:
11x(x+10)-(132)=0
We multiply parentheses
11x^2+110x-132=0
a = 11; b = 110; c = -132;
Δ = b2-4ac
Δ = 1102-4·11·(-132)
Δ = 17908
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{17908}=\sqrt{484*37}=\sqrt{484}*\sqrt{37}=22\sqrt{37}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(110)-22\sqrt{37}}{2*11}=\frac{-110-22\sqrt{37}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(110)+22\sqrt{37}}{2*11}=\frac{-110+22\sqrt{37}}{22} $
| 0.05a+0.9=0.02a+1.8 | | -7w+9=-4(w-3) | | 12-8x=7x-4x | | 6p-4=2p+8 | | 4x+4x-25=3x+15 | | 7(-6p-1)=-p+34 | | 0.50x+18=0.75x+12 | | -19=1-2x+6x | | (3/8)h-8=11 | | 7(1-4r)=-33-8r | | 3(x-1)/2=6(x+3)/12 | | 4z+6=70 | | -27+a=-8(-a+6) | | 210=-14x | | 8y+4y=36+8 | | 3x^2=34x+112 | | 22-7p=-5-3(1-p) | | 8x+2=8(x+5) | | 4(4-5a)=-38+7a | | y+25+2(25+1)=111+25 | | 4c-16+8c=-4 | | 7+4w-9=-6 | | x/6-1=×/6 | | 2(x+6)-5x=21 | | 31-21/2x=16+1/2x | | -5(-8x-2)=-4x-34 | | 19p=190 | | -12=-5-6b+11 | | (1+3s)(4)= | | -7=4u+3(u-7) | | 23y+7y2=20 | | x=18x-6x^2+8 |