-3(3y-6)+3y=7+2(3y-2)

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Solution for -3(3y-6)+3y=7+2(3y-2) equation: 



-3(3y-6)+3y=7+2(3y-2)

We move all terms to the left:

-3(3y-6)+3y-(7+2(3y-2))=0

We add all the numbers together, and all the variables

3y-3(3y-6)-(7+2(3y-2))=0

We multiply parentheses

3y-9y-(7+2(3y-2))+18=0



We calculate terms in parentheses: -(7+2(3y-2)), so:

7+2(3y-2)

determiningTheFunctionDomain
2(3y-2)+7

We multiply parentheses

6y-4+7

We add all the numbers together, and all the variables

6y+3

Back to the equation:

-(6y+3)



We add all the numbers together, and all the variables

-6y-(6y+3)+18=0

We get rid of parentheses

-6y-6y-3+18=0

We add all the numbers together, and all the variables

-12y+15=0

We move all terms containing y to the left, all other terms to the right

-12y=-15

y=-15/-12

y=1+1/4

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