4(u+3)=-2(8u-5)+8u

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Solution for 4(u+3)=-2(8u-5)+8u equation: 



4(u+3)=-2(8u-5)+8u

We move all terms to the left:

4(u+3)-(-2(8u-5)+8u)=0

We multiply parentheses

4u-(-2(8u-5)+8u)+12=0



We calculate terms in parentheses: -(-2(8u-5)+8u), so:

-2(8u-5)+8u

We add all the numbers together, and all the variables

8u-2(8u-5)

We multiply parentheses

8u-16u+10

We add all the numbers together, and all the variables

-8u+10

Back to the equation:

-(-8u+10)



We get rid of parentheses

4u+8u-10+12=0

We add all the numbers together, and all the variables

12u+2=0

We move all terms containing u to the left, all other terms to the right

12u=-2

u=-2/12

u=-1/6

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