-2(u+)=u-1+5(3u+1)

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Solution for -2(u+)=u-1+5(3u+1) equation: 



-2(u+)=u-1+5(3u+1)

We move all terms to the left:

-2(u+)-(u-1+5(3u+1))=0

We add all the numbers together, and all the variables

-2(+u)-(u-1+5(3u+1))=0

We multiply parentheses

-2u-(u-1+5(3u+1))=0



We calculate terms in parentheses: -(u-1+5(3u+1)), so:

u-1+5(3u+1)

determiningTheFunctionDomain
u+5(3u+1)-1

We multiply parentheses

u+15u+5-1

We add all the numbers together, and all the variables

16u+4

Back to the equation:

-(16u+4)



We get rid of parentheses

-2u-16u-4=0

We add all the numbers together, and all the variables

-18u-4=0

We move all terms containing u to the left, all other terms to the right

-18u=4

u=4/-18

u=-2/9

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