-3(-c-12)=-3c

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Solution for -3(-c-12)=-3c equation: 



-3(-c-12)=-3c

We move all terms to the left:

-3(-c-12)-(-3c)=0

We add all the numbers together, and all the variables

-3(-1c-12)-(-3c)=0

We multiply parentheses

3c-(-3c)+36=0

We get rid of parentheses

3c+3c+36=0

We add all the numbers together, and all the variables

6c+36=0

We move all terms containing c to the left, all other terms to the right

6c=-36

c=-36/6

c=-6

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